Question

Solve $ta{n}^2\Theta -si{n}^2\Theta =ta{n}^2\Theta si{n}^2\Theta$

Answer 1

${\tan }^2\theta -{\sin }^2\theta ={\tan }^2\theta {\sin }^2\theta$

$\frac{{\tan }^2\theta }{{\sin }^2\theta }-1={\tan }^2\theta$

$\frac{1}{{\cos }^2\theta }-1={\tan }^2\theta$

$\frac{1-{\cos }^2\theta }{{\cos }^2\theta }=\frac{{\sin }^2\theta }{{\cos }^2\theta }$

${\cos }^2\theta +{\sin }^2\theta =1$