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Byju's Answer
Standard XII
Mathematics
Sign of Trigonometric Ratios in Different Quadrants
Solve: tan 5...
Question
Solve:
tan
5
o
.
tan
15
o
.
tan
45
o
.
tan
75
o
.
t
a
n
85
o
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Solution
tan
5
°
⋅
tan
15
°
⋅
tan
45
°
⋅
tan
75
°
⋅
tan
85
°
=
(
tan
5
°
⋅
tan
85
°
)
⋅
(
tan
15
°
⋅
tan
75
°
)
⋅
tan
45
°
=
(
tan
5
°
⋅
tan
(
90
°
−
5
°
)
)
⋅
(
tan
15
°
⋅
tan
(
90
°
−
15
°
)
)
⋅
tan
45
°
=
(
tan
5
°
⋅
cot
5
°
)
⋅
(
tan
15
°
⋅
cot
15
°
)
⋅
tan
45
°
=
1
×
1
×
1
=
1
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