Question

Solve:
$\tan \theta +\cot \theta =\sec \theta \csc \theta$

Answer 1

$\begin{array}{c}\tan \theta +\cot \theta =\sec \theta .\cos ec\theta \\ \Rightarrow \frac{\sin \theta }{\cos \theta }+\frac{\cos \theta }{\sin \theta }\\ \Rightarrow \frac{{\sin }^2\theta +{\cos }^2\theta }{\sin \theta .\cos \theta }=\frac{1}{\sin \theta .\cos \theta }=\sec \theta .\cos ec\theta Ans.\end{array}$