The correct option is A nπ+π6, n ∈ Z tan x =1√(3) tan x =tanπ6 x=nπ+π6, n∈ Z ...

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Standard Formulae - 1

Solve tan x...

Question

Solve $tan x = \frac{1}{\sqrt{3}}$

n π + \frac{π}{6}, n \in Z

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2 n π + \frac{π}{3}, n \in Z

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n π + \frac{π}{3}, n \in Z

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none of these

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Solution

The correct option is A $n π + \frac{π}{6}, n \in Z$
$tan x = \frac{1}{\sqrt{3}}$

$tan x = tan \frac{π}{6}$

$x = n π + \frac{π}{6}, n \in Z$

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Similar questions

tan x + tan 2 x + \sqrt{3} tan x \cdot tan 2 x = \sqrt{3}

(where n \in Z)

{x \in R : cos 2 x + 2 {cos}^{2} x = 2}

x

{cos}^{2} x = \frac{sin x tan x}{6}

x

tan x - {tan}^{2} x > 0

| 2 sin x | < 1

n \in Z

sec 2 x = \frac{- 2}{\sqrt{3}}

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