Question

Solve that : $\frac{y-4}{3}+3y=4$

Answer 1

Given $\frac{y-4}{3}+3y=4$

$⟹\frac{y-4+3\left(3y\right)}{3}=4$

$⟹\frac{y-4+9y}{3}=4$

$⟹10y-4=12$

$⟹10y=16$

$⟹y=\frac{8}{5}$