Question

Solve the binary division ${\left(101110\right)}_2÷{\left(110\right)}_2$ and also find out remainder and quotient.

• A. ${\left(111\right)}_2$ or ${\left(100\right)}_2$
• B. ${\left(100\right)}_2$ or ${\left(111\right)}_2$
• C. ${\left(101\right)}_2$ or ${\left(101\right)}_2$
• D. ${\left(100\right)}_2$ or ${\left(100\right)}_2$

Answer 1

Answer: (B)

${\left(100\right)}_2$ or ${\left(111\right)}_2$

${\left(101110\right)}_2\to 2^0\times 0+2^1\times 1+2^2\times 1+2^3\times 1+2^4\times 0+2^5\times 1$
$2+4+8+32$
$=46$
${\left(110\right)}_2\to 2^0\times 0+2^1\times 1+2^2\times 1$
$=0+2+4$
$=6$
$\frac{46}{6}=\frac{23}{3}$
quotient $=7\Rightarrow {\left(111\right)}_2$