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Question

Solve the differential equation:
3x2dx+4xydx+2x2dy+2ydy=0.

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Solution

Given the differential equation,
3x2dx+4xydx+2x2dy+2ydy=0
or, 3x2dx+d(2x2y)+2ydy=0
Now integrating both sides we get,
x3+2x2y+y2=c. [ Where c is integrating constant]

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