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Question

Solve the differential equation:
d2ydx2y=0.

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Solution

Given the differential equation is

d2ydx2y=0.

Let y=Aemx for A0 be a trial solution for the given differential equation.

Then we get from the differential equation is

m21=0 [ Auxiliary equation]

or, m=±1.

So the general solution will be

y=c1ex+c2ex. [ Where c1 and c2 are arbitrary constants]

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