CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Solve the differential equation:
d2ydx2y=0.

Open in App
Solution

Given the differential equation is

d2ydx2y=0.

Let y=Aemx for A0 be a trial solution for the given differential equation.

Then we get from the differential equation is

m21=0 [ Auxiliary equation]

or, m=±1.

So the general solution will be

y=c1ex+c2ex. [ Where c1 and c2 are arbitrary constants]

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
General and Particular Solutions of a DE
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon