wiz-icon
MyQuestionIcon
MyQuestionIcon
10
You visited us 10 times! Enjoying our articles? Unlock Full Access!
Question

Solve the differential equation:
dydx+1y2(1+y)2=0.

A
sin1y+x1y2=C
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
x1y22=c
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
x+1y2=c
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
x1y2=c
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A sin1y+x1y2=C
dydx=1y2(1+y)
(1+y)dy1y2=dx
dy1y2+ydy1y2=dx
On integrating, we get
sin1y1y2=x+C
sin1y+x1y2=C

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Basic Theorems in Differentiation
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon