dydx=x5tan−1x3dy=(x5tan−1x3)dxTakingintegrationonbothsides∫dy=∫(x5tan−1x3)dxLetx3=t3x2dx=dty=13∫ttan−1tdt+C=13tan−1t∫tdt−13∫[d(tan−1t)dx∫tdt]dt+C=t26tan−1t−16∫[t2+1−11+t2]dt+C=t22tan−1t−16∫[1−11+t2]dt+C=t22tan−1t−16(t−tan−1t)+Cy=x66tan−1x3−x36+16tan−1(x3)+C.