CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Solve the differential equation dydx=4x3y3x2y.

A
3xyy22x2=c
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
3xy+y22x2=c
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
2xyy22x2=c
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
2xy+y22x2=c
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 3xyy22x2=c
Given equation is dydx=4x3y3x2y
3xdy2ydy=4xdx3ydx3(xdy+ydx)2ydy4xdx=03d(xy)2ydy4xdx=0(3d(xy)2ydy4xdx)=03xyy22x2=c

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Methods of Solving First Order, First Degree Differential Equations
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon