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Question

Solve the differential equation : (yxdydxa(y2+dydx) ) =0

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Solution

yxdydxa(y2dydx)=0yay2=(x+a)dydxdxx+a=dy(yay2)loge(x+a)=2loge2ay4ay4ay2x+a=a2y2aya2y2x+a=ay1ayAns.

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