Question

Solve the distance x of a particle moving in one dimension under the action of a constant force is related to time t by equation t=root over x+3 where x is in metres t is in seconds.Find displacement when velocity is zero.

• A. $2$m
• B. $4$m
• C. $0$m
• D. none of these

Answer 1

The correct option is C $0$m

$t=\sqrt{x}+3$

$\Rightarrow \sqrt{x}=t-3$

$x=t^2-6t+9$

$\frac{dx}{dt}$ is the velocity

$\Rightarrow \frac{dx}{dt}=2t-6$

$v=0$

$2t-6=0$

which will give us $3$ so $t=3$

at $t=3$

$\Rightarrow x=3-3$

so, there will be 0 displacement.

Hence, the answer is $0.$