CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Solve the equality: 2sin11x+cos3x+3sin3x=0

Open in App
Solution

2sin11x+cos3x+3sin3x=0
sin11x+32sin3x+12cos3x=0
sin11x+sin(3x+π6)=0
2sin(7x+π12)cos(4xπ12)=0
sin(7x+π12)=0,cos(4xπ12)=0
7x+π12=xπ,4xπ12=(2x+1)π2
7x=xππ12,4x=(2x+1)π2+π12
x=xπ7π84,x=(2x+1)π8+π48

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Basic Inverse Trigonometric Functions
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon