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Byju's Answer
Standard XII
Mathematics
Domain and Range of Basic Inverse Trigonometric Functions
Solve the equ...
Question
Solve the equality:
2
sin
11
x
+
cos
3
x
+
√
3
sin
3
x
=
0
Open in App
Solution
2
sin
11
x
+
cos
3
x
+
√
3
sin
3
x
=
0
⇒
sin
11
x
+
√
3
2
sin
3
x
+
1
2
cos
3
x
=
0
⇒
sin
11
x
+
sin
(
3
x
+
π
6
)
=
0
⇒
2
sin
(
7
x
+
π
12
)
cos
(
4
x
−
π
12
)
=
0
∴
sin
(
7
x
+
π
12
)
=
0
,
cos
(
4
x
−
π
12
)
=
0
∴
7
x
+
π
12
=
x
π
,
4
x
−
π
12
=
(
2
x
+
1
)
π
2
⇒
7
x
=
x
π
−
π
12
,
4
x
=
(
2
x
+
1
)
π
2
+
π
12
x
=
x
π
7
−
π
84
,
∴
x
=
(
2
x
+
1
)
π
8
+
π
48
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