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Question

Solve the equation

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Solution

The given equation is,

x 2 2x+ 3 2 =0

2 x 2 4x+3=0

Comparing the given equation with a x 2 +bx+c=0 , we get

a=2 b=4 c=3

D= b 2 4ac = ( 4 ) 2 4×2×3 =8

The required solutions are,

x= b± D 2a = ( 4 )±2 2 i 4 = 2± 2 i 2 =1± 2 2 i

Therefore, the solutions to the equation are 1± 2 2 i .


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