Solve the equation
The given equation is,
3 x 2 − 4 x + 20 3 = 0
9 x 2 − 12 x + 20 = 0
Comparing the above equation with a x 2 + b x + c = 0 , we get
a = 9 b = − 12 c = 20
D = b 2 − 4 a c = ( − 12 ) 2 − 4 × 9 × 20 = − 576
The required solutionsare,
x = − b ± D 2 a = − ( − 12 ) ± − 576 2 × 9 = 12 ± 576 i 18 = 12 ± 24 i 18 = 2 3 ± 4 3 i
Therefore, the solutions are 2 3 ± 4 3 i .
The given equation is,
Comparing the above equation with
The required solutionsare,
Therefore, the solutions are
