Solve the equation: $2^{2 x + 3} = {32.2}^{x}$

- 4

No worries! We‘ve got your back. Try BYJU‘S free classes today!

4

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

0

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $2$
$2^{2 x + 3} = 32 \times 2^{x}$
$\Rightarrow 2^{2 x + 3} = 2^{5} \times 2^{x}$
$\Rightarrow 2^{2 x + 3} = 2^{x + 5}$
Since the LHS and RHS have the same base,
$\Rightarrow 2 x + 3 = x + 5$
$\Rightarrow x = 2$

Suggest Corrections

Similar questions

2^{2 x + 8} + 1 = 32 . 2^{x}

2^{2 x} + 2^{x + 2} - 4 \times 2^{3} = 0

x^{4} + 2 x^{3} - 16 x^{2} - 22 x + 7 = 0

2 + \sqrt{3}

40 x^{4} - 22 x^{3} - 21 x^{2} + 2 x + 1 = 0

x^{4} - 2 x^{3} - 21 x^{2} + 22 x + 40 = 0

Join BYJU'S Learning Program