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Question

Solve the equation: 2(2x1x+3)3(x+32x1)=5,(x3,12)

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Solution

2(2x1)23(x+3)2(x+3)(2x1)=5
2(4x2+14x)3(x2+9+6x)
=5(2x2+5x3)
5x226x25=10x2+25x15
5x2+51x+10=0
5x2+50x+x+10=0
5x+(x+10)+1(x+10)=0
(5x+1)(x+10)=0
x=15;x=10

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