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Question

Solve the equation:-
2 tanθcotθ=1

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Solution

2tanθ1tanθ=1
2tan2θ+tanθ1=0
2tan2θ+2tanθtanθ1=0
2tanθ(tanθ+1)(tanθ+1)=0
(tanθ+1)(2tanθ1)=0
tanθ=1,12
θ=π4,3π4,tan1(12)


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