Question

Solve the equation, $2{\text{cos}}^2\theta +3\text{sin}\theta =0$

Or

Solve the equation, ${\text{sec}}^{2}2x=1-\text{tan}2x$

Answer 1

$\theta =n\pi +(-1{)}^n\frac{7\pi }{6},nϵZ$

Or

$x=\frac{n\pi }{2}x=\frac{n\pi }{2}+\frac{3\pi }{8},nϵZ$