Question

Solve the equation $2x+1=x-3$, and represent the solution(s) on
(i) the number line,
(ii) the Cartesian plane

Answer 1

Given$2x+1=x-3$

$\Rightarrow 2x-x=-3-1$ by transposition

$\Rightarrow x=-4$

$\therefore$in the number line $x$ gets the value $-4$ from $0$ to $-4$ units.

In the cartesian plane the point lies at $x-$axis $\therefore$ the $y-$co-ordinate is $0$.

Thus the point $(-4,0)$ lies at negative $x-$axis.