Question

Solve the equation: $2x^2-5x-2=0$.

Answer 1

$2x^2-5x-2=0$

$a=2,b=-5,c=-2$

By using quadratic formula,

$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$x=\frac{-(-5)\pm \sqrt{{(-5)}^2-4\times 2\times (-2)}}{2\times 2}$

$\Rightarrow x=\frac{5\pm \sqrt{24+16}}{4}$

$\Rightarrow x=\frac{5+\sqrt{40}}{4}$ or $x=\frac{5-\sqrt{40}}{4}$