Solve the equation:3(n-5)=21
Find the value of n:
3(n-5)=21
⇒(n-5)=213[Dividingeachsideby3]
⇒(n-5)=7
⇒n=7+5[adding5oneachside]
⇒n=12
Therefore, n=12
Solve linear equation:n2−3n4+5n6=21