Question

Solve the equation $4x^2-5x-3=0$.

Answer 1

Given that,

$4x^2-5x-3=0$

We know that, for a quadratic equation of the form $a{x}^2+bx+c=0$,

$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

Here,

$a=4,b=-5\text{and}c=-3$

$\therefore x=\frac{5\pm \sqrt{(5{)}^2-4(4\left)\right(-3)}}{2\left(4\right)}$

$\Rightarrow x=\frac{5\pm \sqrt{73}}{8}$

$\therefore x=\frac{5-\sqrt{73}}{8}$ or $x=\frac{5+\sqrt{73}}{8}$