Solve the equation:-
$9 (2 x - y)^{2} - 4 (2 x - y) - 13$

Open in App

Solution

$2 x - y = z$
The equation transforms to
$9 z^{2} - 4 z - 13 = 0$
$9 z^{2} - 13 z + 9 z - 13 = 0$
$z (9 z - 13) + 1 (9 z - 13) = 0$
$(9 z - 13) (z + 1) = 0$
$z = \frac{13}{9}$ or $z = - 1$
$∴$ solution of equation are:
$2 x - y = \frac{13}{9}$
$2 x - y = - 1$

Suggest Corrections

Similar questions

9 {(2 x - y)}^{2} - 4 (2 x - y) - 13

9 (2 x - y)^{2} - 4 (2 x - y) - 13

Factorization:

$9 (2 x - 3 y)^{2} - 12 (2 x - 3 y) (2 x + 3 y) + 4 (2 x + 3 y)^{2}$

x^{2} + y^{2} - x y = 13, x + y - \sqrt{x y} = 3

x + 3 y = 9 2 x + y = 8

Join BYJU'S Learning Program