Question

Solve the equation $9x^2-155x-500$ using quadratic method.

Answer 1

By method of quadratic formula;
$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$
Hece, $a=9,b=-155,c=-500$
$x=\frac{-(-155)\pm \sqrt{(-155{)}^2-4\times 9\times (-500)}}{2\times 9}x=\frac{+155\pm \sqrt{24025+218000}}{18}=\frac{+155\pm \sqrt{42025}}{18}=\frac{+155\pm 205}{18}{x}_1=\frac{+155+205}{18}{x}_2=\frac{155-205}{18}=20x_1=\frac{-50}{18}$