Solve the equation by Cramers rule $x + y + z = 1$ , $2 x + 2 y + 3 z = 6$ , $x + 4 y + 9 z = 3$ .

7, - 10, 4

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- 7, - 10, - 4

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7, 10, 4

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7, - 10, - 4

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Solution

The correct option is A $7, - 10, 4$
$Δ = ∣ ∣ ∣ ∣ \begin{matrix} 1 & 1 & 1 2 & 2 & 3 1 & 4 & 9 \end{matrix} ∣ ∣ ∣ ∣ = - 3 Δ_{1} = ∣ ∣ ∣ ∣ \begin{matrix} 1 & 1 & 1 6 & 2 & 3 3 & 4 & 9 \end{matrix} ∣ ∣ ∣ ∣ = - 21 Δ_{2} = ∣ ∣ ∣ ∣ \begin{matrix} 1 & 1 & 1 2 & 6 & 3 1 & 3 & 9 \end{matrix} ∣ ∣ ∣ ∣ = 30 Δ_{3} = ∣ ∣ ∣ ∣ \begin{matrix} 1 & 1 & 1 2 & 2 & 6 1 & 4 & 3 \end{matrix} ∣ ∣ ∣ ∣ = - 12 x = \frac{Δ_{1}}{Δ} = \frac{- 21}{- 3} = 7 y = \frac{Δ_{2}}{Δ} = \frac{30}{- 3} = - 10 z = \frac{Δ_{3}}{Δ} = \frac{- 12}{- 3} = 4$

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Similar questions

x + 2 y + 3 z = 6

2 x + 4 y + z = 7

3 x + 2 y + 9 z = 14

x + y + 3 z = 4; 2 x + 2 y + 6 z = 7; 2 x + y + z = 10

x + y + z = 1, 2 x + 2 y + 3 z = 6, x + 4 y + 9 z = 3

x + 2 y + 3 z = 6, 2 x + 4 y + z = 17, 3 x + 2 y + 9 z = 2

x + y + z

x - 2 y = 10, 2 x + y + 3 z = 8

- 2 y + z = 7

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