Question

Solve the equation by factorize method
$\frac{2}{x^2}-\frac{5}{x}+2$

Answer 1

Given equation is,

$\frac{2}{x^2}-\frac{5}{x}+2=0$

$⟹2x^2-5x+2=0$

$⟹2x^2-4x-x+2=0$

$⟹2x(x-2)-1(x-2)=0$

$⟹(2x-1)(x-2)=0$

$\therefore x=\frac{1}{2}$ or $x=2$