Question

Solve the equation by formula method.
$2x^2-5x+3$

Answer 1

Given equation is,

$2x^2-5x+3=0$

Here, $a=2,b=-5,c=3$

Quadratic formula $x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$⟹x=\frac{-(-5)\pm \sqrt{(-5{)}^2-4(2\left)\right(3)}}{2\left(2\right)}$

$⟹x=\frac{5\pm \sqrt{25-24}}{4}$

$⟹x=\frac{5\pm 1}{4}$

$⟹x=\frac{5+1}{4}$ or $x=\frac{5-1}{4}$

$⟹x=\frac{6}{4}$ or $x=\frac{4}{4}$

$\therefore x=\frac{3}{2}$ or $x=1$