Solve the equation by substitution method
$2 x + 3 y = 9, 3 x + 4 y = 5$

Open in App

Solution

$2 x + 3 y = 9$ (1)

$3 x + 4 y = 5$ (2)

By (1) $2 x = 9 - 3 y$

$x = \frac{9 - 3 y}{2}$

Putting in (2) , we get

$3 (\frac{9 - 3 y}{2}) + 4 y = 5$

$27 - 9 y + 8 y = 10$

$17 = y$

$y = 17$

$x = \frac{9 - 51}{2}$

$= \frac{- 42}{2}$

$x = - 21$

Suggest Corrections

Similar questions

2 x + 3 y = 9

3 x + 4 y = 5

2 x + 3 y = 5

3 x + 4 y = 6

Solve the following system of equations by substitution method:

2x+3y=11
2x−4y=−24

2 x + 3 y = 5, 2 x + 3 y = 7

3 x + 4 y = - 43

- 2 x + 3 y = 11

Join BYJU'S Learning Program