Solve the equation by the square root property.
$x^{2} = 8$

{\sqrt{8}}

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{64}

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{\pm 2 \sqrt{2}}

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{4}

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Solution

The correct option is C ${\pm 2 \sqrt{2}}$
Given, $x^{2} = 8$
$x^{2} - 8 = 0$
By using formula, $a^{2} - b^{2} = (a + b) (a - b)$
$\Rightarrow x^{2} - 8 = (x + 2 \sqrt{2}) (x - 2 \sqrt{2}) = 0$
$\Rightarrow x + 2 \sqrt{2} = 0$ or $x - 2 \sqrt{2} = 0$
So, $x = 2 \sqrt{2}$ or $x = - 2 \sqrt{2}$

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Question 7
Which constant must be added and subtracted to solve the quadratic equation $9 x^{2} + \frac{3}{4} x - \sqrt{2} = 0$ by the method of completing the square?
(A) $\frac{1}{8}$
(B) $\frac{1}{64}$
(C) $\frac{1}{4}$
(D) $\frac{9}{64}$

Question 7
Which constant must be added and subtracted to solve the quadratic equation $9 x^{2} + \frac{3}{4} x - \sqrt{2} = 0$ by the method of completing the square?
(A) $\frac{1}{8}$
(B) $\frac{1}{64}$
(C) $\frac{1}{4}$
(D) $\frac{9}{64}$

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Q. If

α, β

are the roots of the equation

x^{2} - 2 x + 4 = 0

, then the equation whose roots are

α^{3}, β^{3}

Find the square root of i.

Solve the quadratic equation $x^{2} + x + \frac{1}{\sqrt{2}} = 0$

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Solve the equation by the square root property.x2=8

The correct option is C {±2√2}Given, x2=8x2−8=0By using formula, a2−b2=(a+b)(a−b)⇒x2−8=(x+2√2)(x−2√2)=0⇒x+2√2=0 or x−2√2=0So, x=2√2 or x=−2√2

Solve the equation by the square root property.
$x^{2} = 8$

The correct option is C ${\pm 2 \sqrt{2}}$
Given, $x^{2} = 8$
$x^{2} - 8 = 0$
By using formula, $a^{2} - b^{2} = (a + b) (a - b)$
$\Rightarrow x^{2} - 8 = (x + 2 \sqrt{2}) (x - 2 \sqrt{2}) = 0$
$\Rightarrow x + 2 \sqrt{2} = 0$ or $x - 2 \sqrt{2} = 0$
So, $x = 2 \sqrt{2}$ or $x = - 2 \sqrt{2}$