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Question

Solve the equation.
x2+12x+203x5=x2+8x+122x+3

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Solution

We have,
x2+12x+203x5=x2+8x+122x+3

x2+10x+2x+203x5=x2+6x+2x+122x+3

(x+2)(x+10)3x5=(x+6)(x+2)2x+3

(x+10)3x5=(x+6)2x+3

(x+10)(2x+3)=(x+6)(3x5)

2x2+3x+20x+30=3x25x+18x30

x210x60=0

x=10±1004×1×602

x=10±100+2402

x=10±3402

x=10±2852

x=5±85

Hence, this is the answer.

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