Question

Solve the equation. Check your solution.

$\mathrm{n}+\frac{3}{4}=\frac{1}{4}$

Answer 1

Step 1 : Solve the inequality

We have,

$\Rightarrow \mathrm{n}+\frac{3}{4}=14$

$\Rightarrow \mathrm{n}+\frac{3}{4}-\frac{3}{4}=\frac{1}{4}-\frac{3}{4}$ [ Subtract $\frac{3}{4}$ from both sides ]

$$\begin{gathered} \Rightarrow \mathrm{n}=\frac{1-3}{4} \\ \Rightarrow \mathrm{n}=\frac{-2}{4} \end{gathered}$$
$\therefore \mathrm{n}=\frac{-1}{2}$

Step 2 : Checking the solution

Check the solution by putting $\mathrm{n}=\frac{-1}{2}$, in the given inequality

$$\begin{gathered} \Rightarrow \frac{-1}{2}+\frac{3}{4}=\frac{1}{4} \\ \Rightarrow \frac{-2+3}{4}=\frac{1}{4} \\ \Rightarrow \frac{1}{4}=\frac{1}{4} \end{gathered}$$

Hence, the required solution is$\mathrm{n}=\frac{-1}{2}$.