Question

Solve the equation $(\cos x-\sin x)(2\tan x+2)=0$

Answer 1

$(\cos x-\sin x)(2\tan x+2)=0\cos x-\sin x=0\sin x=\cos x\tan x=1x=\frac{\pi }{4}2\tan x+2=0\tan x=-1x=\frac{3\pi }{4}$