Solve the equation- 10x2-15x-635x2-25x-12-2x-3x-5

#160;Consider the given expression. 10x^2+15x+635x^2 25x+12=2x+3x 5 #10; #10; #10; ⇒ #10;10x^3+15x^2+63x 50x^2 75x 315=10x^3 50x^2+24x+15x^2 ...

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Definite Integral as Limit of Sum

Solve the equ...

Question

Solve the equation:
$\frac{10 x^{2} + 15 x + 63}{5 x^{2} - 25 x + 12} = \frac{2 x + 3}{x - 5}$

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\frac{10 x^{2} + 15 x + 63}{5 x^{2} - 25 x + 12} = \frac{2 x + 3}{x - 5}

\frac{10 x^{2} + 15 x + 63}{5 x^{2} - 25 x + 12} = \frac{2 x + 3}{x - 5}

\frac{x^{2} + 12 x - 20}{3 x - 5} = \frac{x^{2} + 8 x + 12}{2 x + 3}

\frac{10 x^{2} + 15 x + 63}{5 x^{2} - 25 x + 12} = \frac{2 x + 3}{x - 5}

\frac{{(2 x + 1)}^{2} + {(2 x - 1)}^{2}}{{(2 x + 1)}^{2} - {(2 x - 1)}^{2}} = \frac{17}{8}

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\frac{{(3 x - 4)}^{3} - {(x + 1)}^{3}}{{(3 x - 4)}^{3} + {(x + 1)}^{3}} = \frac{61}{189}

\frac{10 x^{2} + 15 x + 63}{5 x^{2} - 25 + 12} = \frac{2 x + 3}{x - 5}

3 \sqrt{5} x^{2} + 25 x - 10 \sqrt{5} = 0

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