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Byju's Answer
Standard VIII
Mathematics
Reducing Equations to Simpler Form
Solve the equ...
Question
Solve the equation:
2
z
1
−
z
=
6
A
z
=
1
4
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B
z
=
3
4
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C
z
=
2
4
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D
z
=
3
7
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Solution
The correct option is
A
z
=
3
4
Given,
2
z
1
−
z
=
6
On multiplying both sides by
1
−
z
, we get
2
z
=
6
(
1
−
z
)
2
z
=
6
−
6
z
8
z
=
6
z
=
3
4
Suggest Corrections
0
Similar questions
Q.
4
+
z
−
(
3
+
2
z
)
6
=
−
z
−
3
(
5
−
2
)
7
.
What is the value of
z
in the equation?
Q.
Solve the following system of equations by matrix method:
(i)
x
+
y
−
z
= 3
2
x
+ 3
y
+
z
= 10
3
x
−
y
− 7
z
= 1
(ii)
x
+
y
+
z
= 3
2
x
−
y
+
z
= − 1
2
x
+
y
− 3
z
= − 9
(iii) 6
x
− 12
y
+ 25
z
= 4
4
x
+ 15
y
− 20
z
= 3
2
x
+ 18
y
+ 15
z
= 10
(iv) 3
x
+ 4
y
+ 7
z
= 14
2
x
−
y
+ 3
z
= 4
x
+ 2
y
− 3
z
= 0
(v)
2
x
-
3
y
+
3
z
=
10
1
x
+
1
y
+
1
z
=
10
3
x
-
1
y
+
2
z
=
13
(vi) 5
x
+ 3
y
+
z
= 16
2
x
+
y
+ 3
z
= 19
x
+ 2
y
+ 4
z
= 25
(vii) 3
x
+ 4
y
+ 2
z
= 8
2
y
− 3
z
= 3
x
− 2
y
+ 6
z
= −2
(viii) 2
x
+
y
+
z
= 2
x
+ 3
y
−
z
= 5
3
x
+
y
− 2
z
= 6
(ix) 2
x
+ 6
y
= 2
3
x
−
z
= −8
2
x
−
y
+
z
= −3
(x)
x
−
y
+
z
= 2
2
x
−
y
= 0
2
y
−
z
= 1
(xi) 8
x
+ 4
y
+ 3
z
= 18
2
x
+
y
+
z
= 5
x
+ 2
y
+
z
= 5
(xii)
x
+
y
+
z
= 6
x
+ 2
z
= 7
3
x
+
y
+
z
= 12
(xiii)
2
x
+
3
y
+
10
z
=
4
,
4
x
-
6
y
+
5
z
=
1
,
6
x
+
9
y
-
20
z
=
2
;
x
,
y
,
z
≠
0
(xiv)
x
−
y
+ 2
z
= 7
3
x
+ 4
y
− 5
z
= −5
2
x
−
y
+ 3
z
= 12
Q.
lf
z
4
+
z
3
+
2
z
2
+
z
+
1
=
0
then
|
z
|
=
Q.
Solve the following equations:
2
x
−
4
y
+
9
z
=
28
7
x
+
3
y
−
5
z
=
3
9
x
+
10
y
−
11
z
=
4
Q.
Solve the following equation for
z
.
4
z
−
1
−
5
z
+
2
=
3
z
,
z
≠
1
,
0
,
−
2
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