Question

Solve the equation: $\frac{y-4}{3}+3y=4$

• A. $y=\frac{8}{5}$
• B. $y=5$
• C. $y=10$
• D. $y=\frac{4}{5}$

Answer 1

The correct option is A $y=\frac{8}{5}$

$\frac{y-4}{3}+3y=4$
$\Rightarrow y-4+9y=12$
$\Rightarrow 10y=16$
$\Rightarrow y=\frac{16}{10}=\frac{8}{5}.$