Question

Solve the equation:$\frac{7y+3}{2-5y}=\frac{6}{7}$
$y=$?

• A. $\frac{33}{19}$
• B. $\frac{-8}{17}$
• C. $\frac{-7}{13}$
• D. $\frac{-9}{79}$

Answer 1

Answer: (D)

$\frac{-9}{79}$

Given: $\frac{7y+3}{2-5y}=\frac{6}{7}$

By cross-multiplication method, we get

$7(7y+3)=6(2-5y)$

$\Rightarrow 49y+21=12-30y$

$\Rightarrow 49y+30y=12-21$ ......... [Transposing $-30y$ to LHS and $21$ to RHS]

$\Rightarrow 79y=-9$

$\Rightarrow y=\frac{-9}{79}$