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Question

Solve the equation x2+x+12=0

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Solution

The given quadratic equation is x2+x+12=0
This equation can also be written as 2x2+2x+1=0
On comparing the given equation with ax2+bx+c=0,
we obtain a=2,b=2, and c=1
Therefore, the discriminant D=b24ac=(2)24(2)×1=242
Therefore, the required solutions are
b±D2a=2±2422×2=2±2(122)22
=⎜ ⎜2±2(221i)22⎟ ⎟
=1±1(221)i2

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