Solve the equation. f'(x) \, g'(x) if $f (x) = 3 + 2 x^{2} a n d g (x) 3 x^{2} - (5 x - 3) (2 - x)$

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Solution

given f $(x) = 3 + 2 x^{2}$ , $g (x) = 3 x^{2} - (5 x - 3) (2 - x)$

therefore $d f (x) / d x = 4 x$ , $d g (x) / d x = 16 x - 13$

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Similar questions

f^{'} (x) ⩾ g^{'} (x)

f (x) = 5 - 3 x + \frac{5}{2} x^{2} - \frac{x^{3}}{3}, g (x) = 3 x - 7

f^{'} (x) > g^{'} (x)

f (x) = \frac{1}{2} (5^{2 x + 1})

g (x) = 5^{x} + 4 x (ln 5)

f^{'} (x) > g^{'} (x)

f (x) = (\frac{1}{2}) 5^{2 x + 1}

g (x) = 5^{x} + 4 x log 5

f^{'} (x) > g^{'} (x)

f (x) = (\frac{1}{2}) 5^{2 x + 1}

g (x) = 5^{x} + 4 x log 5 .

f (x) = tan 2 x tan 3 x tan 5 x

f^{'} (x) = 5 {sec}^{2} 5 x - 3 {sec}^{2} 3 x - 2 {sec}^{2} 2 x

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