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Question

Solve the equation for x,y,z and t if 2[xzyt]+3[1102]=3[3546]

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Solution

2[xzyt]+3[1102]=3[3546]
[2x2z2y2t]+[3306]=[9151218]
[2x+32z32y2t+6]=[9151218]
Comparing the corresponding elements of these two matrices, we get:
2x+3=92x=6x=3
2y=12y=6
2z3=152z=18z=9
2t+6=182t=12t=6
x=3,y=6,z=9 and t=6

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