Question

Solve the equation $\frac{1}{2}x+7=11$ by the trial and error method

Answer 1

Solving the equation

A statement of equality which involves one or more variables is called an equation.

Given equation is $\frac{1}{2}x+7=11$

RHS of the equation is $11$ .In LHS, a whole number $7$ is added to $\frac{1}{2}$ of a number $x$.Thus we need to guess several values of $x$ to find the values of LHS that becomes equal to RHS as shown in the table below.

$\mathit{x}$	LHS$\mathbf{=}\frac{\mathbf{1}}{\mathbf{2}}\mathit{x}\mathbf{+}\mathbf{7}$	RHS$\mathbf{=}\mathbf{11}$
$2$	$\frac{1}{2}\times 2+7=8$	$11$
$4$	$\frac{1}{2}\times 4+7=9$	$11$
$6$	$\frac{1}{2}\times 6+7=10$	$11$
$8$	$\frac{1}{2}\times 8+7=11$	$11$

For $x=8$, LHS=RHS.

Thus, $x=8$ is the solution of the equation.

Hence, the solution of the equation $\frac{1}{2}x+7=11$ is $x=8$.