Question

Solve the equation: $\frac{z}{z+15}=\frac{4}{9}$

• A. 12
• B. 15
• C. 10
• D. -12

Answer 1

The correct option is A 12

$\frac{z}{z+15}=\frac{4}{9}$
$\Rightarrow$$9z=4\times (z+15)$
$\Rightarrow$$9z=4z\times 60$
$\Rightarrow$$9z-4z=60$
$\Rightarrow$$5z=60$
$\Rightarrow$$z=\frac{60}{5}=12$

Therefore, required value of $z$ is 12.