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Question

Solve the equation, if ∣ ∣x+axxxx+axxxx+a∣ ∣=0,a0,

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Solution

Given, ∣ ∣x+axxxx+axxxx+a∣ ∣=0∣ ∣3x+a3x+a3x+axx+axxxx+a∣ ∣=0
(using R1R1+R2+R3)
(3x+a)∣ ∣111xx+axxxx+a∣ ∣=0
(Taking out (3x+a) from R1)
(3x+a)∣ ∣100xa0xa0∣ ∣=0, (using C2C2C1 and C3C3C1)
Expanding corresponding to R1 (first row), we get
(3x+a)[1(a×a0)]=0a2(3x+a)=0
But a0 (given). Therefore, 3x+a=0x=a/3


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