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Question

Solve the equation : π2011+4tanxdx=?

A
π/4
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B
π/2
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C
0
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D
1/3
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Solution

The correct option is D π/4
I=π/20dx1+4tanx
=π/20dx1+4cotx
=π/204tanxdx1+4tanx
2I=π/201+4tanx1+4tanxdx
2I=π/2
I=π/4 [A]

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