Solve the equation using formula. $6 m^{2} - 4 m = 3$

m = \frac{- 2 \pm \sqrt{22}}{6}

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m = \frac{- 4 \pm \sqrt{22}}{12}

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m = \frac{2 \pm \sqrt{22}}{6}

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m = \frac{4 \pm \sqrt{22}}{12}

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Solution

The correct option is C $m = \frac{2 \pm \sqrt{22}}{6}$
Given equation is:
$6 m^{2} - 4 m - 3 = 0$
Applying quadratic formula,
$m = \frac{- b \pm \sqrt{b^{2} - 4 a c}}{2 a}$
$a = 6, b = - 4, c = - 3$

$m = \frac{4 \pm \sqrt{16 + 72}}{12}$
$m = \frac{4 \pm 2 \sqrt{22}}{12}$
$m = \frac{2 \pm \sqrt{22}}{6}$

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Solve the equation using formula. 6m2−4m=3

The correct option is C m=2±√226Given equation is:6m2−4m−3=0Applying quadratic formula,m=−b±√b2−4ac2aa=6,b=−4,c=−3m=4±√16+7212m=4±2√2212m=2±√226

Solve the equation using formula. $6 m^{2} - 4 m = 3$