Solve the equation using substitution method:
$x + y = - 3$ and $x + 2 y = 4$

-10 and 7

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10 and 7

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10 and -7

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-10 and -7

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Solution

The correct option is A -10 and 7
$x + y = - 3$ ------(1)
$x + 2 y = 4$ ------(2)
From equation (1)
$x + y = - 3$
$y = - 3 - x$
Substitute the value of $y$ in equation (2)
$x + 2 y = 4$
$x + 2 (- 3 - x) = 4$
$x - 6 - 2 x = 4$
$- x = 4 + 6$
$x = - 10$
Substitute the value of $x$ in equation (1)
$x + y = - 3$
$- 10 + y = - 3$
$y = - 3 + 10$
$y = 7$
Therefore solution is $x = - 10$ and $y = 7$

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Similar questions

Solve the following pair of linear equations by the elimination method and the substitution method :

(i) x+y=5 and 2x−3y=4
(ii) 3x+4y=10 and 2x−2y=2
(iii) 3x−5y−4=0 and 9x=2y+7
(iv) x2+2y3=−1 and x−y3=3

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5 x - 2 y = 10

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\frac{x + 11}{7} + 2 y = 10, 3 x = 8 + \frac{y + 7}{11}

x - y = 3

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