Solve the equation using the quadratic formula
$3 x^{2} = - 10 x - 5$

{\frac{- 5 \pm \sqrt{10}}{3}}

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{\frac{- 10 \pm \sqrt{10}}{3}}

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{\frac{- 10 \pm \sqrt{10}}{6}}

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{\frac{- 5 \pm \sqrt{10}}{6}}

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Solution

The correct option is A ${\frac{- 5 \pm \sqrt{10}}{3}}$
Given equation $3 x^{2} = - 10 x - 5$
$⟹ 3 x^{2} + 10 x + 5 = 0$ .
When this equation is compared with general equation $a x^{2} + b x + c = 0$
$a = 3$ , $b = 10$ and $c = 5$
Quadratic formula given by sri dharacharya, $x = \frac{- b \pm \sqrt{b^{2} - 4 a c}}{2 a} .$
on substituting values we get,
$x = \frac{- 5 \pm \sqrt{10}}{3} .$

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