Solve the equation
$(x - 1)^{3} = 64$

Open in App

Solution

Given, $(x - 1)^{3} = 64$

$(x - 1)^{3} = 4^{3}$

$x - 1 = 4$

$x = 4 + 1 = 5$

Suggest Corrections

Similar questions

{3 x}^{{log}_{5} 2} + 2^{{log}_{5} x} = 64

x

3. x^{l o g_{5} 2} + 2^{l o g_{5} x} = 64

\frac{{(3 x - 4)}^{3} - {(x + 1)}^{3}}{{(3 x - 4)}^{3} + {(x + 1)}^{3}} = \frac{61}{189}

log (64 \sqrt[24]{2^{x^{2} - 40 x}}) = 0

\frac{3}{2^{log x}} = \frac{1}{64}

Join BYJU'S Learning Program